answer:To find the concentration of the HCl solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between HCl and NaOH: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l) From the balanced equation, we can see that one mole of HCl reacts with one mole of NaOH. We are given the volume and concentration of the NaOH solution, so we can find the moles of NaOH: moles of NaOH = volume (L) × concentration (M) moles of NaOH = 0.035 L × 0.1 M = 0.0035 moles Since the ratio of HCl to NaOH is 1:1, the moles of HCl that reacted are also 0.0035 moles. Now we can find the concentration of the HCl solution using the volume of the HCl solution: concentration of HCl = moles of HCl / volume of HCl (L) concentration of HCl = 0.0035 moles / 0.025 L = 0.14 M So, the concentration of the HCl solution is 0.14 M.

answer:To find the concentration of the hydrochloric acid (HCl) solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between sodium hydroxide (NaOH) and hydrochloric acid (HCl): NaOH + HCl → NaCl + H2O From the balanced equation, we can see that the mole ratio between NaOH and HCl is 1:1. First, we need to find the moles of NaOH used in the reaction: moles of NaOH = volume (L) × concentration (M) moles of NaOH = 0.025 L × 0.100 M moles of NaOH = 0.0025 moles Since the mole ratio between NaOH and HCl is 1:1, the moles of HCl in the reaction are also 0.0025 moles. Now, we can find the concentration of the HCl solution using the formula: concentration (M) = moles of HCl / volume of HCl solution (L) First, convert the volume of HCl solution from mL to L: 30.0 mL = 0.030 L Now, find the concentration of HCl: concentration (M) = 0.0025 moles / 0.030 L concentration (M) = 0.0833 M Therefore, the concentration of the hydrochloric acid (HCl) solution is 0.0833 M.

answer:To find the concentration of the HCl solution, we can use the balanced chemical equation for the neutralization reaction between HCl and NaOH: HCl (aq) + NaOH (aq) → NaCl (aq) + H2O (l) From the balanced equation, we can see that the mole ratio between HCl and NaOH is 1:1. This means that the moles of HCl required to neutralize the NaOH is equal to the moles of NaOH. Given that 0.015 moles of NaOH are neutralized, we also have 0.015 moles of HCl. Now, we can use the formula for concentration: Concentration (mol/L) = moles of solute / volume of solution (L) First, we need to convert the volume of the HCl solution from mL to L: 25.00 mL = 0.025 L Now, we can calculate the concentration of the HCl solution: Concentration (mol/L) = 0.015 moles / 0.025 L = 0.6 mol/L So, the concentration of the HCl solution is 0.6 mol/L.

answer:To find the concentration of the HCl solution, we can use the concept of stoichiometry and the balanced chemical equation for the reaction between NaOH and HCl: NaOH + HCl → NaCl + H2O From the balanced equation, we can see that the mole ratio between NaOH and HCl is 1:1. First, we need to find the moles of NaOH used in the titration: moles of NaOH = volume (L) × concentration (moles/L) moles of NaOH = 0.025 L × 0.10 moles/L = 0.0025 moles Since the mole ratio between NaOH and HCl is 1:1, the moles of HCl that reacted with NaOH are also 0.0025 moles. Now, we can find the concentration of the HCl solution: concentration (moles/L) = moles of HCl / volume of HCl solution (L) concentration (moles/L) = 0.0025 moles / 0.020 L = 0.125 moles/L The concentration of the HCl solution is 0.125 moles/L.