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question:What is the corrosion rate of an iron rod with a surface area of 25 cm² when it is placed in a saltwater solution for 48 hours, and the weight loss is 8.5 grams? Given that the density of iron is 7.87 g/cm³ and the atomic weight of iron is 55.85 g/mol. Calculate the corrosion rate in mm/year.

answer:To calculate the corrosion rate in mm/year, we need to follow these steps: 1. Calculate the volume loss of the iron rod. 2. Calculate the penetration depth. 3. Calculate the corrosion rate in mm/year. Step 1: Calculate the volume loss of the iron rod. Volume loss = Weight loss / Density of iron Volume loss = 8.5 g / 7.87 g/cm³ Volume loss ≈ 1.08 cm³ Step 2: Calculate the penetration depth. Penetration depth = Volume loss / Surface area Penetration depth = 1.08 cm³ / 25 cm² Penetration depth ≈ 0.0432 cm Step 3: Calculate the corrosion rate in mm/year. First, we need to convert the penetration depth from cm to mm: Penetration depth = 0.0432 cm * 10 mm/cm Penetration depth ≈ 0.432 mm Now, we need to convert the time from hours to years: Time in years = 48 hours * (1 day/24 hours) * (1 year/365 days) Time in years ≈ 0.00548 years Finally, we can calculate the corrosion rate: Corrosion rate = Penetration depth / Time in years Corrosion rate = 0.432 mm / 0.00548 years Corrosion rate ≈ 78.83 mm/year The corrosion rate of the iron rod in the saltwater solution is approximately 78.83 mm/year.

question:What is the corrosion rate in millimeters per year (mm/year) of a carbon steel pipe with a surface area of 3 square meters, exposed to a solution containing 300 ppm (parts per million) of dissolved oxygen at a temperature of 30°C for 5 years? Given that the weight loss due to corrosion is 10 grams and the density of carbon steel is 7.85 g/cm³.

answer:To calculate the corrosion rate in mm/year, we need to follow these steps: 1. Convert the weight loss to volume loss. 2. Calculate the volume loss per year. 3. Calculate the average thickness loss per year. 4. Convert the thickness loss to mm/year. Step 1: Convert the weight loss to volume loss Weight loss = 10 g Density of carbon steel = 7.85 g/cm³ Volume loss = Weight loss / Density Volume loss = 10 g / 7.85 g/cm³ Volume loss = 1.2739 cm³ Step 2: Calculate the volume loss per year Total years = 5 years Volume loss per year = Volume loss / Total years Volume loss per year = 1.2739 cm³ / 5 years Volume loss per year = 0.2548 cm³/year Step 3: Calculate the average thickness loss per year Surface area = 3 m² = 30000 cm² (1 m² = 10000 cm²) Thickness loss per year = Volume loss per year / Surface area Thickness loss per year = 0.2548 cm³/year / 30000 cm² Thickness loss per year = 0.000008493 cm/year Step 4: Convert the thickness loss to mm/year 1 cm = 10 mm Corrosion rate = Thickness loss per year * 10 Corrosion rate = 0.000008493 cm/year * 10 Corrosion rate = 0.00008493 mm/year The corrosion rate of the carbon steel pipe is approximately 0.00008493 mm/year.

question:The problem for the chemistry student to solve is: What is the corrosion rate of iron (Fe) in a sea environment if it loses 5 grams of mass during one month?

answer:To calculate the corrosion rate of iron (Fe) in a sea environment, we can use the following formula: Corrosion rate (CR) = (Weight loss (WL) × Equivalent weight (EW) × K) / (Area (A) × Time (T)) Where: - Weight loss (WL) is the mass loss of the iron due to corrosion (5 grams in this case) - Equivalent weight (EW) is the atomic weight of iron divided by the number of electrons lost during the corrosion process (for iron, the atomic weight is 55.85 g/mol and it typically loses 2 electrons during corrosion, so EW = 55.85/2 = 27.925 g/equivalent) - K is a constant to convert the units (for the corrosion rate in mm/year, K = 3.27 × 10^6 mm^3/(g·year·m^2)) - Area (A) is the surface area of the iron exposed to the sea environment (we need this value to proceed) - Time (T) is the duration of the exposure (1 month, which is approximately 1/12 of a year or 0.0833 years) To solve the problem, we need the surface area (A) of the iron exposed to the sea environment. If you provide this value, we can calculate the corrosion rate.

question:What is the corrosion rate (in mm/year) of a steel pipe (density=7850 kg/m³, area=0.5 m²) in contact with a hydrochloric acid solution with a pH of 2.5 and a temperature of 25°C, if the measured current density is 0.003 A/m²? Assume a Faraday's constant of 96500 C/mol and a molar mass of iron of 56 g/mol.

answer:To calculate the corrosion rate, we can use the following formula: Corrosion rate (mm/year) = (Current density * Molar mass * Equivalent weight * 10) / (Density * Area * Faraday's constant) First, we need to find the equivalent weight of iron. Since iron has a valency of +2, the equivalent weight will be: Equivalent weight = Molar mass / Valency Equivalent weight = 56 g/mol / 2 Equivalent weight = 28 g/mol Now we can plug in the values into the formula: Corrosion rate (mm/year) = (0.003 A/m² * 56 g/mol * 28 g/mol * 10) / (7850 kg/m³ * 0.5 m² * 96500 C/mol) Corrosion rate (mm/year) = (0.003 * 56 * 28 * 10) / (7850 * 0.5 * 96500) Corrosion rate (mm/year) = (4.704) / (189162.5) Corrosion rate (mm/year) ≈ 0.00002486 mm/year The corrosion rate of the steel pipe in contact with the hydrochloric acid solution is approximately 0.00002486 mm/year.

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